HARD
JEE Main/Advance
IMPORTANT
Earn 100

A uniform cylinder of length L and thermal conductivity k is placed on a metal plate of the same area S of mass m and infinite conductivity. The specific heat of the plate is c. The top of the cylinder is maintained at T0. Find the time required for the temperature of the plate to rise from T1 to T2 (T1<T2<T0).

Important Questions on Heat Transfer

EASY
JEE Main/Advance
IMPORTANT
Assume that the total surface area of a human body is 1.6 m2 and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37 °C. Stefan constant σ is 6.0 × 108 W m-2 K-4 . (31)4 = 923521)
MEDIUM
JEE Main/Advance
IMPORTANT
The surface of a household radiator has an emissivity of 0.55 and an area of 1.5 m2. (a) At what rate is radiation emitted by the radiator when its temperature is 50 °C? (b) At what rate is the radiation absorbed by the radiator when the walls of the room are at 22 °C? (c) What is the net rate of radiation from the radiator? (Stefan's constant σ=6×108 W m-2 K4)
EASY
JEE Main/Advance
IMPORTANT
A man, the surface area of whose skin is 2 m2 is sitting in a room where the air temperature is 20 °C. If the skin temperature is 28 °C, find the net rate at which his body loses heat. [Take the emissivity of skin 0.97 and Stefan’s constant =5.67×108 W m-2 K4].
MEDIUM
JEE Main/Advance
IMPORTANT
An electric heater is used in a room of total wall area 137 m2 to maintain a temperature of +20 °C inside it, when the outside temperature is -10 °C. The walls have three different layers of materials. The innermost layer is of wood of thickness 2.5 cm, the middle layer is of cement of thickness 1.0 cm and the outermost layer is of brick of thickness 25.0 cm. Find the power of electric heater. Assume that there is no heat loss through the floor and the ceiling. The thermal conductivities of wood, cement and brick are 0.125,1.5 and 1.0 W m-1°C-1, respectively.
HARD
JEE Main/Advance
IMPORTANT
A rod of length l with thermally insulated lateral surface, consists of a material whose heat conductivity coefficient varies with temperature as k=aT, where a is a constant. The ends of the rod are kept at temperatures T1 and T2. Find the function Tx, where x is the distance from the end whose temperature is T1.
HARD
JEE Main/Advance
IMPORTANT
Two chunks of metal with heat capacities C1 and C2 are interconnected by a rod of length l and cross-sectional area S and fairly low heat conductivity χ. The whole system is thermally insulated from the environment. At a moment t=0, the temperature difference between the two chunks of metal equals ΔT0. Assuming the heat capacity of the rod to be negligible, find the temperature difference between the chunks, as a function of time.
HARD
JEE Main/Advance
IMPORTANT

It is well known that the temperature of a closed room goes up if the refrigerator is switched on inside it. A refrigerator compartment set to temperature Tc is turned on inside a hut in Leh (Ladakh). The atmosphere (outside the hut) can be considered to be a vast reservoir at constant temperature To. Walls of hut and refrigerator compartment are conducting. The temperature of the refrigerator compartment is maintained at Tc with the help of a compressor engine. We explain the working of the refrigerator engine and the heat flow with the help of the associated figure.

Question Image

The larger square is the refrigerator compartment with heat leak per unit time Qc into it from the room. The same heat per unit time Qc is pumped out of it by the engine (also called compressor and indicated by the smaller square in thick). The compressor does work W and rejects heat per unit time QH into the hut. The thermal conductance (in units of watt per Kelvin) of the walls of the compartment and hut respectively are Kc and KH. After a long time it is found that temperature of the hut is TH. The compressor works as a reverse Carnot engine and it does not participate in heat conduction process.

(a) State the law of heat conduction for the walls of the hut and the refrigerator compartment. 

(b) We define the dimensionless quantities k = KHKc, h=THTo and c=TcTo. Express h in terms of c and k.

(c) Calculate stable temperature TH given To=280.0 K, Tc=252.0 K and k=0.90.