Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Two metallic spheres are charged to the same potential. One of them is hollow and another is solid, and both have the same radii. Solid sphere will have lower charge than the hollow one. Reason R : Capacitance of metallic spheres depend on the radii of spheres. In the light of the above statements, choose the correct answer from the options given below.

Both A and R are true and R is the correct explanation of A

Both A and R are true but R is not the correct explanation of A

Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region E I , E I I and E I I I

E → I = - σ ∈ 0 n ^ , E → I I = 0 , E → I I I = σ ∈ 0 n ^

E → I = 2 σ ∈ 0 n ^ , E → I I = 0 , E → I I I = 2 σ ∈ 0 n ^

E → I = 0 , E → I I = σ ∈ 0 n ^ , E → I I I = 0

E → I = σ 2 ∈ 0 n ^ , E → I I = 0 , E → I I I = σ 2 ∈ 0 n ^

Considering a group of positive charges, which of the following statements is correct?

Net potential of the system cannot be zero at a point but net electric field can be zero at that point

Net potential of the system at a point can be zero but net electric field can't be zero at that point

Both the net potential and the net field can be zero at a point

Both the net potential and the net electric field cannot be zero at a point

HARD

JEE Main

IMPORTANT

Earn 100

A uniformly charged disc of radius $R$ having surface charge density $σ$ is placed in the $x y$ plane with its center at the origin. Find the electric field intensity along the $z$ -axis at a distance $Z$ from origin:

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Important Questions on Electrostatics

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 27 August 2021 Shift 2>Q 6

Figure shows a rod $A B$ , which is bent in a $120 °$ circular arc of radius $R$ . A charge $(- Q)$ is uniformly distributed over rod $AB$ . What is the electric filed $\vec{E}$ at the centre of curvature $O$ ?

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EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 27 August 2021 Shift 2>Q 7

Three capacitors $C_{1} = 2 μ F, C_{2} = 6 μ F$ and $C_{3} = 12 μ F$ are connected as shown in the figure. Find the ratio of the charges on capacitors $C_{1}, C_{2}$ and $C_{3}$ respectively.

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MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 31 August 2021 Shift 1>Q 8

Two particles

A

and

B

having charges

20 μ C

and

- 5 μ C

respectively are held fixed with a separation of

5 cm

At what position a third charged particle should be placed so that it does not experience a net electric force ?
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MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 31 August 2021 Shift 1>Q 10

A capacitor of

50 μ F

is connected in a circuit as shown in figure. The charge on the upper plate of the capacitor is _________

μ C .

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 31 August 2021 Shift 2>Q 11

Choose the incorrect statement:
(a) The electric lines of force entering into a Gaussian surface provide negative flux.
(b) A charge $q$ is placed at the centre of a cube. The flux through all the faces will be the same.
(c) In a uniform electric field net flux through a closed Gaussian surface containing no net charge, is zero.
(d) When an electric field is parallel to a Gaussian surface, it provides a finite non-zero flux.

Choose the most appropriate answer from the options given below:

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 1 September 2021 Shift 2>Q 13

A cube is placed inside an electric field, $\vec{E} = 150 y^{2} \hat{j}$ The side of the cube is $0.5 m$ and is placed in the field as shown in the given figure. The charge inside the cube is:

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MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 1 September 2021 Shift 2>Q 14

A capacitor is connected to a

20 V

battery through a resistance of

10 Ω .

It is found that the potential difference across the capacitor rises to

2 V

1 μs .

The capacitance of the capacitor is

________μF .

Given In

(\frac{10}{9}) = 0.105

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 13 - Electrostatics>JEE Main - 20 July 2021 Shift 1>Q 15

A certain charge

Q

is divided into two parts

q

and

(Q - q) .

How should the charges

Q

and

q

be divided so that

q

and

(Q - q)

placed at a certain distance apart experience maximum electrostatic repulsion?

A uniformly charged disc of radius R having surface charge density σ is placed in the xy plane with its center at the origin. Find the electric field intensity along the z-axis at a distance Z from origin:

Important Questions on Electrostatics

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A uniformly charged disc of radius $R$ having surface charge density $σ$ is placed in the $x y$ plane with its center at the origin. Find the electric field intensity along the $z$ -axis at a distance $Z$ from origin: