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A variable force, $F = 25 t$ acts on a body of mass $10 kg$ kept on a rough horizontal surface $(μ_{s} = 0.6, μ_{k} = 0.4)$ . The velocity of the body at $t = 4 s$ is,

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Important Questions on Laws of Motion

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 3

In the situation shown in the diagram, the system is in equilibrium. All the strings, spring and pulley are light. Just after cutting the string

A B

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 4

Match the following (Take the relative strength of the strongest fundamental forces in nature as one)

I	II
Fundamental forces in nature	Relative strength
(A) Strong nuclear force	(e) $10^{- 2}$
(B) Weak nuclear force	(f) $1$
(C) Electromagnetic force	(h) $10^{-13}$
(D) Gravitational force	(i) $10^{- 39}$

The correct match is

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 5

Let

F

F_{N}

and

f

denote the magnitudes of the contact force, normal force and the frictional force exerted by one surface on the other kept in contact. If none of these is zero, then:

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 6

Two boys of masses

10 kg

and

8 kg

are moving along a vertical rope, the former climbing up with the acceleration of

2 m s^{- 2}

while the later coming down with a uniform velocity of

2 m s^{- 1}

. Then tension in the rope at the fixed support is (Take

g = 10 m s^{- 2}

)

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 7

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 8

In a situation, the contact force by a rough horizontal surface, on a body placed on it, has constant magnitude. If the angle between this force and the vertical is decreased, the frictional force between the surface and the body will

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 9

A block is on a rough inclined plane. To keep it at rest force required is maximum

2 N

downward or maximum

10 N

upward. Find the coefficient of friction

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 10

A variable force

F = 25 t

acts on a body of mass

10 kg

kept on a rough horizontal surface

(μ_{s} = 0.6, μ_{k} = 0.4)

. The velocity of the body at

t = 4 s

is,

A variable force, F=25t acts on a body of mass 10 kg kept on a rough horizontal surface μs=0.6 μk=0.4. The velocity of the body at t=4s is,

Important Questions on Laws of Motion

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A variable force, $F = 25 t$ acts on a body of mass $10 kg$ kept on a rough horizontal surface $(μ_{s} = 0.6, μ_{k} = 0.4)$ . The velocity of the body at $t = 4 s$ is,