$AD$ is a median of the triangle $ABC$. The smallest distance of $AD$ from $B \text{and} C$ are $BP \text{and} CQ$ respectively. Let's prove that $BP=CQ$.

Observe the lengths of the given sides and write whether it is possible to draw a triangle or not?

$3 \mathrm{cm},6 \mathrm{cm}$ and $8 \mathrm{cm}$

Observe the lengths of the given sides and write whether it is possible to draw a triangle or not?

$8 \mathrm{cm},6 \mathrm{cm}$ and $15 \mathrm{cm}$

Observe the lengths of the given sides and write whether it is possible to draw a triangle or not?

$2.7 \mathrm{cm},6.1 \mathrm{cm}$ and $8.8 \mathrm{cm}$

Observe the lengths of the given sides and write whether it is possible to draw a triangle or not?

$2.5 \mathrm{cm},8 \mathrm{cm}$ and $6 \mathrm{cm}$