According to the Kirchhoff's laws in an electric circuit, the algebraic sum of current at any junction is

The figure shows a network of currents. The magnitude of currents is shown here. The current $I$ will be

Consider the circuit shown in the figure. The current $I_{3}$ is equal to

In the circuit shown, the current through the $5 \mathrm{\Omega }$ resistor is

Kirchhoff's current law is the law of conservation of 

The potential difference $\left(V_{\mathrm{A}}-V_{\mathrm{B}}\right)$ between the points $A$ and $B$ in the given figure is

$\mathrm{A}$, $\mathrm{B}$ and $\mathrm{C}$ are voltmeters of resistance $R$, $1.5R$ and $3R$ respectively as shown in the figure. When some potential difference is applied between $\mathrm{X}$ and $Y$, the voltmeter readings are $V_{\mathrm{A}}$, $V_{\mathrm{B}}$ and $V_{\mathrm{C}}$ respectively, then

A certain wire is made up into two squares with a common side of length $5 \mathrm{cm}$. A current $I$ enters the rectangular network at one of the corners and leaves at the diagonally opposite corner. The current in the common side in terms of the entering current is

A circuit contains an ammeter, a battery of $30 \mathrm{V}$ and a resistance $40.8 \mathrm{\Omega }$ all connected in series. If the ammeter has a coil of resistance $480 \mathrm{\Omega }$ and a shunt of $20 \mathrm{\Omega }$, the reading in the ammeter will be