Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 285

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According to the laws of Boolean algebra, the expression $(A + A B)$ is equal to

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Important Questions on Semiconductors

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 286

The Boolean equation for the circuit given in the figure is

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 288

If

A = 1, B = 0,

then in terms of Boolean algebra

A B + \bar{A} \cdot A

equals

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 289

The boolean equation for the circuit given in figure is

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 290

The boolean expression

\bar{A B C}

can be simplified as-

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 291

To get an output $y = 0$ from the circuit shown in the figure, the input $C$ must be

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 292

The output $Y$ of the logic circuit shown in the figure is best represented as-

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 295

Which logic gate is similar to a function of two series switches?

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Physics Crash Course MHT-CET>Chapter 24 - Semiconductors>Exercise 1>Q 299

An

OR

gate gives a logic

1

output