The hybridizations of ' C ' and ' O ' in CO and CO 2 respectively are:

CO : C = sp ; O = sp and CO 2 : C = sp ; O = sp 2

CO : C = sp O = sp and CO 2 : C = sp 2 ; O = sp 2

CO : C = sp O = sp 2 and CO 2 : C = sp ; O = sp 2

CO : C = sp 2 O = sp 2 and CO 2 : C = sp ; O = sp

Molecule Hybridization Geometry (a) BCl 3 (i) sp 3 (p) distorted octahedron (b) BrCl 3 (ii) sp 2 (q) Pyramidal (c) NH 3 (iii) sp 3 d (r) Trigonal Planar (d) XeF 6 (iv) sp 3 d 2 (s) T-shaped

(a-ii-r), (b-iii-s), (c-i-q), (d-iv-p)

(a-ii-r), (b-ii-p), (c-i-q), (d-iv-s)

(a-iv-s), (b-i-r), (c-ii-p), (d-iii-q)

(a-i-p), (b-iv-s), (c-ii-q), (d-iii-r)

The bond lengths (in pm ) of C - C , C ≡ C and C = C are:

C - C C ≡ C C = C 154 120 133

C - C C ≡ C C = C 120 154 133

C - C C ≡ C C = C 154 120 139

C - C C ≡ C C = C 140 133 139

The hybridizations of ' C ' and ' O ' in CO and CO 2 respectively are:

CO : C = sp ; O = sp and CO 2 : C = sp ; O = sp 2

CO : C = sp O = sp and CO 2 : C = sp 2 ; O = sp 2

CO : C = sp O = sp 2 and CO 2 : C = sp ; O = sp 2

CO : C = sp 2 O = sp 2 and CO 2 : C = sp ; O = sp

Molecule Hybridization Geometry (a) BCl 3 (i) sp 3 (p) distorted octahedron (b) BrCl 3 (ii) sp 2 (q) Pyramidal (c) NH 3 (iii) sp 3 d (r) Trigonal Planar (d) XeF 6 (iv) sp 3 d 2 (s) T-shaped

(a-ii-r), (b-iii-s), (c-i-q), (d-iv-p)

(a-ii-r), (b-ii-p), (c-i-q), (d-iv-s)

(a-iv-s), (b-i-r), (c-ii-p), (d-iii-q)

(a-i-p), (b-iv-s), (c-ii-q), (d-iii-r)

Arrange the following ions in the correct order of X - O bond order. where ' X ' denotes the central atom.

SiO 4 4 - < PO 4 3 - < SO 4 2 - < ClO 4 -

SiO 4 4 - < SO 4 2 - < PO 4 3 - < ClO 4 -

ClO 4 - < SO 4 2 - < PO 4 3 - < SiO 4 4 -

ClO 4 - < PO 4 3 - < SO 4 2 - < SiO 4 4 -

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Among the aliphatic hydrocarbons $C_{2} H_{6}, C_{2} H_{4}, {CH}_{4}$ and $C_{2} H_{2}$ the pair having hybrid orbitals to unhybridised orbitals ratio $1 : 1$ is

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Important Questions on Chemical Bonding and Molecular Structure

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET Medical 2021 (6-Sep Afternoon)>Q 8

The hybridization of the central atom in the species $1 {Cl}_{2}^{+}$ is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET - 3 Sep 2021 Forenoon>Q 9

If a molecule has trigonal bipyramidal shape, the hybridization is ________

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET - 3 Sep 2021 Afternoon>Q 10

The hybridizations of

' C'

and

' O'

CO

and

{CO}_{2}

respectively are:

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET Medical 2018 (22-Apr Shift-1)>Q 12

A molecule

(X)

is represented as

{AB}_{5} E

and molecule

(Y)

is shown as

{AB}_{4} E_{2} .

X

and

Y

. the electron pair arrangement around the central atom

' A'

is respectively

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET Medical 2019 (24-Apr Shift-1)>Q 13

Identify the correct pair of molecules in which central atom of each has same number of lone pair of electrons but with different shapes

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET - 3 Sep 2021 Afternoon>Q 16

Molecule		Hybridization		Geometry
(a)	${BCl}_{3}$	(i)	${sp}^{3}$	(p)	distorted octahedron
(b)	${BrCl}_{3}$	(ii)	${sp}^{2}$	(q)	Pyramidal
(c)	${NH}_{3}$	(iii)	${sp}^{3} d$	(r)	Trigonal Planar
(d)	${XeF}_{6}$	(iv)	${sp}^{3} d^{2}$	(s)	T-shaped

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET Medical 2021 (6-Sep Afternoon)>Q 3

Assuming $AB$ is an ionic compound and $r_{c}, r_{a}$ are the ionic radii of $A^{+}$ and $B^{-}$ respectively. The lattice energy of the compound $AB$ is proportional to:

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 4 - Chemical Bonding and Molecular Structure>AP EAPCET Medical 2018 (22-Apr Shift-1)>Q 5

The bond lengths (in $pm)$ of $C - C, C \equiv C$ and $C = C$ are:

Among the aliphatic hydrocarbons C2H6,C2H4,CH4 and C2H2 the pair having hybrid orbitals to unhybridised orbitals ratio 1: 1 is

Important Questions on Chemical Bonding and Molecular Structure

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Among the aliphatic hydrocarbons $C_{2} H_{6}, C_{2} H_{4}, {CH}_{4}$ and $C_{2} H_{2}$ the pair having hybrid orbitals to unhybridised orbitals ratio $1 : 1$ is