MEDIUM
AS and A Level
IMPORTANT
Earn 100

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J. Calculate the potential difference that an α-particle, initially at rest, would have to be accelerated through to gain this energy.

Important Questions on Coulomb's Law

MEDIUM
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J. Calculate the speed of the a-particle at this kinetic energy.

EASY
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J.

(b) This diagram shows the path of an α-particle of this energy as it approaches a gold nucleus head-on.

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(i) State the speed of the α-particle at its point of closest approach to the gold nucleus.

MEDIUM
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J.

(b) This diagram shows the path of an α-particle of this energy as it approaches a gold nucleus head-on.

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(ii) Write down the kinetic energy of the α-particle at this point.

EASY
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J.

(b) This diagram shows the path of an α-particle of this energy as it approaches a gold nucleus head-on.

Question Image

(iii) Write down the potential energy of the α-particle at this point.

EASY
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J. Show that the α-particle will reach a distance of 4.5×10-14m from the centre of the gold nucleus.

EASY
AS and A Level
IMPORTANT

An α-particle emitted in the radioactive decay of radium has a kinetic energy of 8.0×10-13J.

(d) Suggest and explain what this information tells us about the gold nucleus.

(Mass of an α -particle =6.65×10-27 kg; charge on an α -particle =+2e; charge on a gold nucleus =+79e.)

MEDIUM
AS and A Level
IMPORTANT

This graph shows the electrical potential near an antiproton.

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(i) Determine the potential at a distance .053×10-10m from the antiproton.