MEDIUM
JEE Main
IMPORTANT
Earn 100

An acidic solution of dichromate is electrolysed for 8 minutes using 2 A current. As per the following equation

Cr2O72-+14H++6e-2Cr3++7H2O
The amount of Cr3+obtained was 0.104g. The efficiency of the process (in%) is (Take : F=96000 C, At. mass of chromium =52)

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Important Questions on Electrochemistry

MEDIUM
JEE Main
IMPORTANT
Let CNaCl and CBaSO4, be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO4 respectively, at a temperature T. Which of the following is false?
HARD
JEE Main
IMPORTANT

The photoelectric current from Na (work function, w0=2.3eV)  is stopped by the output voltage of the cell

Pt(s)H2(g,1bar)|HCl(aq·,pH=1)|AgCl(s)Ag(s)
the pH of aq. HCl required to stop the photoelectric current from Kw0=2.25eV, all other conditions remaining the same, is .×10-2 (to the nearest integer).

Given 2.303RTF=0.06V;EAgCl/Ag/Cl0=0.22V

EASY
JEE Main
IMPORTANT
Given
ECl2/Cl-o=1.36V, ECr3+/Cro= -0.74V
ECr2O72-/Cr3+o=1.33V, EMnO4-/Mn2+o=1.51V.
Among the following, the strongest reducing agent is:
EASY
JEE Main
IMPORTANT

For the cell Cu(s)Cu2+(aq)(0.1M)Ag+(aq)(0.01M)Ag(s) the cell potential E1=0.3095 V. For the cell Cu(s)Cu2+(aq)(0.01M)Ag+(aq)(0.001M)Ag(s) the cell potential =x×10-2 V. Find value of x (Round off the Nearest Integer).

[ Use :2.303RTF=0.059 J ]

MEDIUM
JEE Main
IMPORTANT
The conductivity of a weak acid HA of concentration 0.001 mol L-1 is 2.0×10-5 S cm-1. If Λm0(HA)=190 S cm2 mol-1, the ionization constant Ka of HA is equal to ____ ×10-6
(Round off to the Nearest Integer)
MEDIUM
JEE Main
IMPORTANT
The resistance of conductivity cell with cell constant 1.14 cm-1, containing 0.001M KCl at 298 K is 1500Ω. The molar conductivity of 0.001M KCl solution at 298 K in S cm2 mol-1 is (Integer answer)
MEDIUM
JEE Main
IMPORTANT

Emf of the following cell at 298 K in V is x×10-2

ZnZn2+0.1MAg+0.01MAg

The value of x is ________________ (Rounded off to the nearest integer)

Given: EZn2+/Znθ=-0.76 V; EAg+/Agθ=+0.80 V;  2.303RTF=0.059

EASY
JEE Main
IMPORTANT

Consider the following reaction

MnO4-+8H++5e-Mn+2+4H2O ,E°=1.51 V

The quantity of electricity required in Faraday to reduce five moles of MnO4- is