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An alternating current is given by i=i1sinωt+i2cosωt. The RMS current is given by

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Important Questions on Alternating Current

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For an AC given by I=50cos100t+45° A. The value of Irms= _________ A.
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An alternating current is given by the equation i=i1sinωt+i2cosωt. The rms current will be:
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An AC source rated 220 V,50 Hz is connected to a resistor. The time taken by the current to change from its maximum to the rms value is :
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A 10 Ω resistance is connected across 220 V-50 Hz AC supply. The time taken by the current to change from its maximum value to the rms value is:
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The RMS value of emf given by E=(8sinωt+6cosωt) volt is
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A pure inductor of inductance 0.1 H is connected to an AC source (of rms voltage) 220 V angular frequency of 300 Hz. The rms current is
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An AC current is given by I=I1sinωt+I2cosωt.
A hot wire ammeter will give a reading:
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An alternating current is given by i=2sinωt+6cosωt. The R.M.S. current in amperes is,
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An AC source is rated at 220 V, 50 Hz. The time taken for voltage to change from its peak value to zero is
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The rms value of potential difference V0 shown in figure is

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If the mains voltage is 230 V, then the peak voltage approximately is
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A 40 μF capacitor is connected to a 200 V, 50 Hz AC supply. The rms value of the current in the circuit is, nearly:
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The alternating current is given by, i=42sin2πTt+10 A. The R.M.S. value of this current is __________ A.

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An A.C. voltage V=5cos(1000t) V is applied to a L-R series circuit of inductance 3 mH and resistance 4 Ω. The value of maximum current in the circuit is _____ A.
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A bulb of resistance 280Ω is supplied with a 200 V AC supply. What is the peak current?
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The alternating current in a circuit is given by the equation i=10sin100πt+π6. The current attains its first maximum at t is:

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A resistance of 20 Ω is connected to an alternating current source of 110 V. If the frequency of the A.C. source is 50 Hz, then the time taken by the current to change from its maximum value to the R.M.S. value is
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The mean or average value of AC over a complete cycle is
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In the given circuit the peak voltages across C, L and R are 30 V, 110 V and 60 V respectively. The rms value of the applied voltage is

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HARD
The instantaneous voltages at three terminals marked X, Y and Z are given by

VX=V0sinωt

VY=V0sinωt+2π3  and

VZ=V0sinωt+4π3.

An ideal voltmeter is configured to read rms value of the potential difference between its terminals. It is connected between points X and Y and then between Y and Z . The reading(s) of the voltmeter will be