An alternating voltage $V\left(t\right)=220\sin \left(100\pi t\right)$ volt is applied to a purely resistive load of $50 \mathrm{\Omega }$ . The time taken for the current to rise from half of the peak value to the peak value is:

The rms value of potential difference $V_0$ shown in figure is

In the given circuit the peak voltages across $C, L$ and $R$ are $30 \mathrm{V}, 110 \mathrm{V}$ and $60 \mathrm{V}$ respectively. The rms value of the applied voltage is