Name: Practical Problems on Division of Numbers
Uploaded: 2019-07-19
Duration: 3 min 36 s
Description: Dividing numbers is as simple as equally dividing a pizza with your friends! Watch the video to understand the practical applications of the division of two...

Question

An atom changes to a charged particle called ion if it loses or gains electrons. The charge on an ion is the charge on electrons plus charge on protons. Now, write the missing information in the table given below:

$\begin{matrix} Name of Ion & Proton Charge & Electron Charge & Ion Charge \\ Hydroxide ion & + 9 & - & - 1 \\ Sodium ion & + 11 & - & + 1 \\ Aluminium ion & + 13 & - 10 & - \\ Oxide ion & + 8 & - 10 & - \end{matrix}$

Accepted Answer

The missing data given in table,

$\begin{array}{l} Name of lon & \begin{array}{l} Proton \\ Charge \end{array} & \begin{array}{l} Electron \\ Charge \end{array} & \begin{array}{l} Ion \\ Charge \end{array} \\ Oxide ion & + 8 & - 10 & + 8 - 10 = - 2 \\ Hydroxide ion & + 9 & - 1 - 9 = - 10 & - 1 \\ Sodium ion & + 11 & + 1 - 11 = - 10 & + 1 \\ Aluminium ion & + 13 & - 10 & + 13 - 10 \\ = + 3 \end{array}$

$Ion charge = Proton charg e + Electron charge$

$(a)$ Hydroxideion

$Proton charge = + 9 Ion charge = - 1 Ion charge = Proton charge + Electron charge electron charge = Ion charge - Proton charge electron charge = - 1 - (+ 9) = - 1 - 9 = - 10$

$(b)$ Sodium ion

$Proton charge = + 11 Ion charge = + 1 Ion charge = Proton charge + Electron charge electron charge = Ion charge - Proton charge electron charge = + 1 - (+ 11) = 1 - 11 = - 10$

$(c)$ Aluminium ion

$Proton charge = + 13 electron charge = - 10 Ion charge = Proton charge + Electron charge electron charge = + 13 + (- 10) = 13 - 10 = + 3$

$(d)$ Oxide ion

$Proton charge = + 8 electron charge = - 10 Ion charge = Proton charge + Electron charge Ion charge = + 8 + (- 10) = - 2$

Chapter-Wise 3D Mathematics Videos from NCERT NCERT Exemplar Mathematics - Class 7

Practical Problems on Division of Numbers

Division of Two Numbers

Product of Two Negative Integers

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