If ∮ s E → . ds → = 0 over a surface then-

all charges must be outside the surface.

the electric field inside and outside the surface is zero.

the electric field inside the surface is necessarily uniform.

MEDIUM

Earn 100

An electric dipole is placed at the centre of a spherical shell. Mark the correct options.

50% studentsanswered this correctly

Important Questions on Electrostatics

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

The electric field in a region is given by

\vec{E} = \frac{2}{5} E_{0} \hat{i} + \frac{3}{5} E_{0} \hat{j}

with

E_{0} = 4.0 \times 10^{3} N C^{- 1} .

The flux of this field through a rectangular surface, area

0.4 m^{2}

parallel to the

Y - Z

plane is _______

N m^{2} C^{- 1}

HARD

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A point charge

+ Q

is placed just outside an imaginary hemispherical surface of radius R as shown in the figure. Which of the following statements is/are correct?

Question Image

HARD

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

The electric field in a region is given by

\vec{E} = (\frac{3}{5} E_{0} \hat{i} + \frac{4}{5} E_{0} \hat{j}) N C^{- 1}

. The ratio of flux of reported field through the rectangular surface of area

0.2 m^{2}

(parallel to

y - z

plane) to that of the surface of area

0.3 m^{2}

(parallel to

x - z

plane) is

a : b = a : 2,

where

a = ?

[Here

\hat{i}, \hat{j}

and

\hat{k}

are unit vectors along

x, y

and

z

-axes respectively]

MEDIUM

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

An electric field

\vec{E} = [4 x \hat{i} - (y^{2} + 1) \hat{j}] N C^{- 1}

passes through the box shown in figure. The flux of the electric field through surfaces

A B C D

and

B C G F

are marked as

ϕ_{I}

and

ϕ_{I I}

respectively. The value of

|ϕ_{I} - ϕ_{I I}|

is (in

N m^{2} C^{- 1}

) ____________.
Question Image

HARD

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

Consider a sphere of radius

R

which carries a uniform charge density

ρ

. If a sphere of radius

\frac{R}{2}

is carved out of it, as shown, the ratio

\frac{|\vec{E_{A}}|}{|\vec{E_{B}}|}

of magnitude of electric field

\vec{E_{A}}

and

\vec{E_{B}}

, respectively, at points

A

and

B

due to the remaining portion is:

Question Image

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about

150 N / C

, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be : [Given :

\in_{O} = 8.85 \times 1 0^{- 12} C^{2} / {N-m}^{2}, R_{E} = 6.37 \times 1 0^{6} m

]

HARD

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A circular disc of radius

R

carries surface charge density

σ (r) = σ_{0} (1 - \frac{r}{R})

, where

σ_{0}

is a constant and

r

is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is

ϕ_{0}

. Electric flux through another spherical surface of radius

\frac{R}{4}

and concentric with the disc is

ϕ

. Then the ratio

\frac{ϕ_{0}}{ϕ}

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A charge $q$ is placed at one corner of a cube as shown in figure. The flux of electrostatic field $\vec{E}$ through the shaded area is:

Question Image

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A point charge $q$ is placed at the corner of a cube of side $a$ as shown in the figure. What is the electric flux through the face $A B C D$ ?

Question Image

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

The electric field in a region of space is given by,

\vec{E} = E_{0} \hat{i} + 2 E_{0} \hat{j}

where

E_{0} = 100 N C^{- 1}

. The flux of this field through a circular surface of radius

0.02 m

parallel to the

Y ‐ Z

plane is nearly

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

Four closed surfaces and corresponding charge distributions are shown below.

Question Image

Let the respective electric fluxes through the surfaces be

ϕ_{1}, ϕ_{2}, ϕ_{3}

and

ϕ_{4}

. Then:

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

\oint_{s} \vec{E} . \vec{ds} = 0

over a surface then-

MEDIUM

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

An infinitely long line charge having linear charge density

λ

lies at a distance

d

from center of an imaginary sphere of radius

R

. Then

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

MEDIUM

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

A charged particle

q

is placed at the centre $O$ of a cube of length $L$

(ABCDEFGH)

. Another same charge $q$ is placed at a distance $L$ from $O$ . If the total electric flux through the cube is

6 ϕ

then the value of

ϕ

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

In the figure, a hemispherical bowl of radius $R$ is shown. Electric field of intensity $E$ is represented in each situation by direction lines.

Question Image

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

If there were only one type of charge in the universe, then

HARD

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

Three infinitely long charge sheets are placed as shown in the figure. The electric field at the point $P$ is

Question Image

MEDIUM

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

Consider an electric field

\vec{E} = E_{0} \hat{x}

, where

E_{0}

is a constant. The flux through the shaded area (as shown in the figure) due to this field is

Question Image

EASY

Physics>Electricity and Magnetism>Electrostatics>Flux of Electric Field

Figure shows, in cross section, two Gaussian spheres and two Gaussian cubes that are centered on a positively charged particle. Select the correct alternatives.

Question Image

An electric dipole is placed at the centre of a spherical shell. Mark the correct options.

Important Questions on Electrostatics

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