Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 25

EASY

JEE Main/Advance

IMPORTANT

Earn 100

An electric field exists in space as $E = 2 \hat{i} + 3 \hat{j} + 0 \hat{k} .$ Find the potential difference $(V_{A} - V_{B})$ between points $A (2, 2, 0)$ and $B (1, 1, 0) .$

50% studentsanswered this correctly

Important Questions on Electrostatic Potential and Capacitance

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 26

The electric potential in space is given by

V (x, y, z) = (2 x y + y^{2} z + x^{2} y z)

volt, where

x, y

and

z

are in metre. Then

y

component of electric field at the point

(3, - 2, 1)

will be

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 27

The electrostatic potential difference between points

A

and

B, V_{A} - V_{B},

which are distances

r_{A} = 2.0 m

and

r_{B} = 1.0 m

from an infinitely long thin wire

λ = 1.0 μ C / m

is

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 28

In the above situation (i.e., Q. 27), if an electron is released from rest at point

A

it's speed at point

B

will be

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 31

A uniform electric field having a magnitude

E_{0}

, directed along positive x-axis exists. If the electric potential

V

is zero at

x = 0

, then its value at

x = + x

will be

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 32

The electric potential

V

at any point

(X, Y, Z)

in space is given by

V = 4 x^{2} V

. the electric field at

(1, 0, 2)

m in

{Vm}^{- 1}

is

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.3>Q 33

In an electric field, potential at a point with position vector

\vec{r}

is given as

v = \frac{343}{| \vec{r} |}

. The electric field at

\vec{r} = 3 \hat{i} + 2 \hat{j} + 6 \hat{k}

is

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.4>Q 34

Consider a hollow spherical conductor that has a potential of

300

volts at its outside surface. The potential inside the hollow must be

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 16 - Electrostatic Potential and Capacitance>EXERCISE 2.4>Q 37

Two copper spheres of same radii (one hollow and other solid) are charged to the same potential then