EASY

12th CBSE

IMPORTANT

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An electron after being accelerated through a potential difference of $100 V$ enters a uniform magnetic field of $0.004 T$ perpendicular to its direction of motion. Calculate the radius of the path described by the electron.

Important Questions on Magnetic Effect of Current

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 3

A particle having a charge of

100 μ C

μC and a mass of

10 mg

is projected in a uniform magnetic field of

25 m T

with a speed of

10 {ms}^{- 1}

in a direction perpendicular to the field. What will be the period of revolution of the particle in the magnetic field?

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 4

An electron having a kinetic energy of

100 e V

circulates in a path of radius

10 cm

in a magnetic field. Find the magnetic field and the number of revolutions made by the electron per second.

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 5

An electron beam passes through a magnetic field of

2 \times 10^{- 3} W b m^{- 2}

and an electric field of

1.0 \times 10^{4} V m^{- 1}

, both acting simultaneously. If the path of the electrons remains undeviated, calculate the speed of the electrons. If the electric field is removed, what will be the radius of the circular path?

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 6

An electron moving perpendicular to a uniform magnetic field completes a circular orbit in

10^{- 6} s

. Calculate the value of the magnetic field. Mass of electron

= 9 \times 10^{- 31} kg

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 7

Find the flux density of the magnetic field to cause

62.5 e V

electron to move in a circular path of radius

5 cm

. Given

m_{e} = 9.1 \times 10^{- 31} kg

and

e = 1.6 \times 10^{- 19} C

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 8

An electron of energy

2000 e V

describes a circular path in a magnetic field of

0.2 T

. What is the radius of path? Take

m_{e} = 9 \times 10^{- 31} kg, e = 1 .6 \times 10^{- 19} C

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 9

What should be the minimum magnitude and direction of the magnetic field that must be produced at the equator of earth so that a proton may go around the earth with a speed of

1.0 \times 10^{7} {ms}^{- 1}

? Earth’s radius is

6.4 \times 10^{6} m .

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 4 - Magnetic Effect of Current>Problems For Practice>Q 10

A stream of charged particles possessing a range of speeds enters region $I$ after passing through a slit $S_{1}$ (Fig. $4.67$ ). In $I$ region I there exist crossed (perpendicular) electric and magnetic fields. The electric field has magnitude $100 V m^{- 1}$ We want the particles emerging from slit $S_{2}$ into region $I I$ to have a fixed velocity of $1000 {ms}^{- 1}$ . What should be the value of the uniform magnetic field in region $I$ ?

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An electron after being accelerated through a potential difference of 100 V enters a uniform magnetic field of 0.004 T perpendicular to its direction of motion. Calculate the radius of the path described by the electron.

Important Questions on Magnetic Effect of Current

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An electron after being accelerated through a potential difference of $100 V$ enters a uniform magnetic field of $0.004 T$ perpendicular to its direction of motion. Calculate the radius of the path described by the electron.