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Earn 100

An electron has an energy of 100 eV. What will be its wavelength?

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Important Questions on Dual Nature of Matter and Radiation

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The ratio of wavelength of deuteron and proton accelerated through the same potential difference will be,
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An electron is accelerated from rest between two points A and B with the potentials 20 V and 40 V respectively. The de-Broglie's wavelength associated with the electron at B will be,
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An electron is moving with velocity 6.6×103 m s-1. The de-Broglie wavelength associated with the electron is (mass of electron=9×1031 kg, Planck's constant=6.62×1034 J s),
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The energy that should be added to an electron to reduce its de-broglie's wavelength from 10-10 m to 0.5×10-10 m will be,
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The magnitude of the de-Broglie's wavelength λ of an electron (e) , a proton p, a neutron n and an α-particle (α), all having the same kinetic energy of 1 MeV, in the increasing order will follow the sequence,
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The accelerating voltage of an electron gun is 50000 V. The de-Broglie's wavelength of the electron will be,
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If the mass of neutron, mn=1.7×10-27 kg, then the de Broglie wavelength of neutron of energy 3 eV is,
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A proton and an α-particle are accelerated through same voltage. The ratio of their de-Broglie wavelength will be,