Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 2

EASY

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IMPORTANT

Earn 100

An electron revolves around a nucleus of charge $Z e$ . In order to excite the electron from the state $n = 3$ to $n = 4$ , the energy required is $66.0 eV$ . Then atomic number $Z$ is

26.8% studentsanswered this correctly

Important Questions on Atoms and Nuclei

EASY

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 3

Rutherford's

α

-scattering experiment concludes that_____.

EASY

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 4

Angular momentum of an electron in hydrogen atom is

\frac{3 h}{2 π}

(

h

is the Planck's constant). The K.E. of the electron is

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 5

The density of nucleus is of the order of

HARD

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 6

In the hydrogen atom spectrum

λ_{3 - 1}

and

λ_{2 - 1}

represent wavelengths emitted due to transition from second and first excited states to the ground state respectively. The value of

\frac{λ_{3 - 1}}{λ_{2 - 1}}

is

N / 32,

then sum of digits in N is?

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 7

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 8

The ratio of the longest to the shortest wavelengths in the Brackett series of hydrogen spectra is:

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 9

The shortest wavelength in Lyman series is

91 .2 nm

. The longest wavelength of the series is

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IMPORTANT

Physics Crash Course JEE Main>Chapter 21 - Atoms and Nuclei>Level 2>Q 10

A hydrogen atom is in the

4^{th}

excited state, then: