Find electric field intensity due to an electric dipole of moment 16 . 9 × 10 - 7 Cm at a distance of 12 cm from its centre on its equator if the length of the dipole is 10 cm .

q = 106 . 2 μC = 106 . 2 × 10 - 16 C Total flux through cube ϕ Flux through 6 force ϕ = q ∈ ∘ = 106 . 2 × 10 - 6 8 . 85 × 10 - 12 = 106 . 2 × 10 6 8 . 85 NC - 1 m 2 = 12 × 10 6 NC - 1 m 2 now , Flux through 1 face ⇒ ϕ = 1 6 × ϕ = 1 6 × 12 × 10 6 NC - 1 m 2 = 2 × 10 6 NC - 1 m 2

E M B I B E

Bureau's Higher Secondary Physics Class 12>Chapter 2 - Electric Field and Potential>MODEL QUESTIONS>Q 28

EASY

12th Odisha Board

IMPORTANT

Earn 100

An electrostatic field line cannot be discontinuous. Why?

Important Questions on Electric Field and Potential

EASY

12th Odisha Board

IMPORTANT

Bureau's Higher Secondary Physics Class 12>Chapter 2 - Electric Field and Potential>MODEL QUESTIONS>Q 29

Figure below shows three point charges $+ 2 q, - q & + 3 q$ . Two charge $+ 2 q & q$ are enclosed within a surface $S$ . What is electric flux due to this configuration through the surface $S$ ?

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EASY

12th Odisha Board

IMPORTANT

Bureau's Higher Secondary Physics Class 12>Chapter 2 - Electric Field and Potential>MODEL QUESTIONS>Q 30

An electric dipole of dipole moment

20 \times 10^{- 6} C . m

Is enclosed by a closed surface. What is the net electric flux coming out of this surface ?

EASY

12th Odisha Board

IMPORTANT

Bureau's Higher Secondary Physics Class 12>Chapter 2 - Electric Field and Potential>MODEL QUESTIONS>Q 1

Find electric field intensity in which an electron experiences a force equivalent to its own weight.

(m_{e} = 9.1 \times 10^{- 31} kg)

.

EASY

12th Odisha Board

IMPORTANT

Bureau's Higher Secondary Physics Class 12>Chapter 2 - Electric Field and Potential>MODEL QUESTIONS>Q 2

Three small spheres each carrying a charge $q$ Are placed on the circumference of a circle of radius $r$ To form an equilateral triangle. Find the electric field at the centre of the circle.

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