An imaginary equilateral triangle $ABC$ of side length $2 \mathrm{m}$ is placed in a uniform electric field $\overrightarrow{\mathrm{E}}=10 \mathrm{N} {\mathrm{C}}^{-1}$ as shown. Then. $V_A-V_B=$

As shown in the figure below, a point charge $q$ moves from point $P$ to a point $S$ traversing a path $PQRS$ in a uniform $\overrightarrow{E}.$ The electric field is directed along a direction parallel to $x$-axis. The coordinates of, $P,Q,R$ and $S$ are $\left(a,b,0\right)\left(2a,0,0\right)\left(a,-b,0\right)$ and $\left(0,0,0\right)$ respectively. What is the work done by the field in the process?

Figure shows three arrangements of electric field lines. In each arrangement, a proton is released from rest at point A and then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. If $p_1,p_2$ and $p_3$ are linear momentum of the proton at point B in the three arrangement respectively, then

In the electric field of a point charge $q$ which is located at center of sphere as shown, a certain charge is carried from point $A$ to $B, C, D$ and $E$. Then work done by external agent