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An inductance of 0.4 Henry and a resistance of 100 ohm are connected to a A.C. voltage source of 220 V and 50 Hz. Then find out the phase difference between the voltage and current flowing in the circuit : 

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Important Questions on Alternating Current

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A capacitor of capacitance 100 μF and resistance of 100 Ω is connected in series with AC supply of 220 V, 50 Hz. The current leads the voltage by-
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If the current through an inductor of inductance L is given by I=I0sinωt, then the voltage across the inductor will be:- 
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There is a 5Ω resistance in an A.C., circuit. Inductance of 0.1 H is connected with it in series. If equation of A.C. e.m.f. is 5 sin 50 t then the phase difference between current and e.m.f. is :- 
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200 Ω resistance and 1 H inductance are connected in series with an A.C. circuit. The frequency of the source is 2002π. Then phase difference in between V and I will be: 
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An inductance of 1 mH, a condenser of 10 μF and a resistance of 50 Ω are connected in series. The reactance of inductor and condensers are same. The reactance of either of them will be
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A circuit contains R, L and C connected in series with an A. C. source. The values of the reactances for inductor and capacitor are 200 Ω and 600 Ωrespectively and the impedance of the circuit is Z1. What happens to the impedance of the same circuit if the values of the reactances are interchanged:- 
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An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, the applied voltage: