EASY
JEE Main/Advance
IMPORTANT
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An infinitely long wire carries current i0 along +z axis. Find flux through the right angled isosceles triangular region coplanar with the wire as shown in figure.

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Important Questions on Electromagnetic Induction

EASY
JEE Main/Advance
IMPORTANT

The loop moves towards a region of magnetic field. Draw graph of i(+ ve direction is marked in figure ) and time. Speed of coil is constant and equal to v ..

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MEDIUM
JEE Main/Advance
IMPORTANT

The loop shown in figure is rotating with angular velocity ω around a perpendicular axis passing through O. Which of the following graph correctly represent emf developed in the loop as function of θ ? ( θ is shown in diagram) (Consider anti-clockwise current due to + ve emf)

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MEDIUM
JEE Main/Advance
IMPORTANT

A rod is moving on rails as shown in figure. Outside magnetic field is given by B0. Resistance of system is R and length is l .

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(a) Find direction of induced current.
(b) Find emf and current.
(c) Find magnetic force on the rod.

EASY
JEE Main/Advance
IMPORTANT

The wire is shaped like a parabola y2=4ax, and the magnetic field is uniform and out of the plane of the paper perpendicularly. At the instant the rod crosses the point (a, 0). Induced emf in the rod is

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MEDIUM
JEE Main/Advance
IMPORTANT
A straight segment of wire is moving with velocity i^-2j^+k^ and magnetic field in the region is 4i^+2j^-k^. Find emf induced in rod at an instant when points are located between (1,1,1) and (3,3,3) .
MEDIUM
JEE Main/Advance
IMPORTANT

Magnetic field in a cylindrical region is given by B=αt. Find emf across rod AB as shown in figure.

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HARD
JEE Main/Advance
IMPORTANT

A charge q, mass m is lying in a cylindrical region of magnetic field at point P. If magnetic field in the region is given by B0 and P is at distance R from centre of region, find speed of charge if the magnetic field is suddenly switched off

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EASY
JEE Main/Advance
IMPORTANT

Network shown in the diagram is part of an electrical circuit. The current is 2 A and is decreasing at the rate of 2 As then VP-VQ equals

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