An iron ring having 500 turns of wire and a mean diameter of 12 cm carries a current of 0 . 3 A . The relative permeability of iron is 600 . What is the magnetic flux density in the core ? What is the magnetisation field intensity? What part of the flux density is due to the electronic loop currents in the core?

Given: Number of turns, N = 500 The mean diameter of the ring, d = 12 cm Current in the winding, I = 0 .3 A Flux through the ring, ϕ = 2 × 10 - 6 Wb The relative permeability of iron, μ r = 600 The magnetising field intensity, H = n I = N I . I = N π D . I = 500 × 0 .3 π × 0 .12 = 397 .9 A turns m - 1 Magnetic flux density, B = μ H = μ r μ 0 H = 600 × 4 π × 10 - 7 × 397 .9 = 0 .3 Wb m - 1 Flux density due to electronic current loop is μ 0 M = B - μ 0 H = 0 .3 - 4 π × 10 - 7 × 397 . = 0 .3 - 0 .0005 = 0 .2995 Wb m - 2

E M B I B E

New Simplified Physics (Vol 1) For Class 12>Chapter 5 - Magnetism>Problems For Practice>Q 6

EASY

12th CBSE

IMPORTANT

Earn 100

An iron ring of mean circumferential length $30 cm$ and cross-section $1 {cm}^{2}$ is wound uniformly with $300$ turns of wire. When a current of $0.032 A$ flows in the windings; the flux in the ring is $2 \times 10^{- 6} Wb$ . Find the flux density in the ring, magnetising field intensity and relative permeability of iron.

Important Questions on Magnetism

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 5 - Magnetism>Problems For Practice>Q 7

An iron ring having

500

turns of wire and a mean diameter of

12 cm

carries a current of

0.3 A

. The relative permeability of iron is

μ_{r} = \frac{μ}{μ_{0}} = \frac{6 .25 \times 10^{- 4}}{4 π \times 10^{- 7}} = 500

. What is the magnetic flux density in the core ? What is the magnetisation field intensity? What part of the flux density is due to the electronic loop currents in the core?