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An object of specific gravity ρ is hung from a thin steel wire. The fundamental frequency for transverse standing waves in the wire is 300 Hz. The object is immersed in water so that one half of its volume is submerged. The new fundamental frequency (in Hz) is:

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Important Questions on Wave Motion on a String

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A circular loop of rope of length L rotates with uniform angular velocity ω about axis through its centre on a horizontal smooth platform. Velocity of pulse (with respect to rope) produced due to sight radial displacement is given by

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Three waves of equal frequency having amplitudes 10 μm4 μm and 7 μm arrive at a given point with a successive phase difference of π2. The amplitude of the resulting wave in μm is given by

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A metalled wire with tension T and at temperature 30ºC vibrates with its fundamental frequency of 1 kHz. The same wire with the same tension but at 10°C temperature vibrates with a fundamental frequency of 1.001 kHz. The cofficient of linear expansion of the wire is
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A steel wire of length 1 m and mass 0.1 kg and having a uniform cross-sectional area of 10-6 m2 is rigidly fixed at both ends. The temperature of the wire is lowered by 20ºC if the transverse waves are set up plucking the string in the middle the frequency of the fundamental note of vibration is

Ysteel =2×1011N/m2 αsteel=1.21×10-5/ºC

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A heavy but uniform rope of length L is suspended from a ceiling. A particle is dropped from the ceiling at the instant when the bottom end is given the jerk. Where will the particle meet the pulse :
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A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive X direction. The transverse velocity of the particle at x=0 as a function of time is shown. The amplitude of the motion is

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A 20 cm long rubber string obeys Hook's law. Initially, when it is stretched to make its total length of 24 cm, the lowest frequency of resonance is ν. It is further stretched to make its total length of 26 cm. The lowest frequency of resonance will now be:
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The wave-function for a certain standing wave on a string fixed at both ends is y(x, t)=0.5sin(0.025πx)cos500t where x and y are in centimeters and t is in seconds. The shortest possible length of the string is: