An uncharged capacitor is connected to a battery. On charging the capacitor :-

A parallel plate capacitor has rectangular plates of 400 cm² area and are separated by a distance of 2 mm with air as the medium. What charge will appear on the plates if a 200 volt potential difference is applied across the capacitor ?

There are two metallic plates of a parallel plate capacitor. One plate is given a charge $+q$ while the other is earthed as shown. Points $P, P_1$ and $P_2$ are taken as shown in the adjoining figure. Then the electric intensity is not zero at:

The distance between the plates of a circular parallel plate capacitor of diameter, $40 \mathrm{mm}$, whose capacity is equal to that of a metallic sphere of radius, $1 \mathrm{m}$ will be:

The energy density in a parallel plate capacitor is given as $2.1 \times {10}^{-9} \mathrm{J} {\mathrm{m}}^{-3}$. The value of the electric field in the region between the plates is :

A charged parallel plate capacitor of distance $\left(d\right)$ has $U_0$ energy. A slab of dielectric constant $\left(K\right)$ and thickness$\left(d\right)$ is then introduced between the plates of the capacitor. The new energy of the system is given by :

The energy and capacity of a charged parallel plate capacitor are $U$ and $C$ respectively. Now a dielectric slab of ${\mathrm{\epsilon }}_{\mathrm{r}}=6$ is inserted in it then energy and capacity becomes : (Assuming charge on plates remains constant)