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As shown in the figure, a disc of mass m is rolling without slipping with an angular velocity ω. The portion AB is rough and BC is smooth. When it crosses point B disc will be in :

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Important Questions on Rotational Mechanics

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A cylinder rolls up an inclined plane, reaches some height and then rolls down (without slipping throughout these motions). The directions of the frictional force acting on the cylinder are
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A solid uniform disc of mass m rolls without slipping down a fixed inclined plank with an acceleration a. The frictional force on the disc due to the surface of the plane is
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A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc

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A drum of radius R and mass M, rolls down without slipping along an inclined plane of angle θ. The frictional force
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A round uniform body of radius R, mass M and moment of inertia I, rolls down (without slipping) an inclined plane making an angle $\theta$ with the horizontal. Then, its acceleration is
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A smooth inclined plane fixed in a car accelerating on a horizontal road is shown in figure. The angle of incline θ is related to the acceleration a of the car as a=gtanθ. If the sphere is set in pure rolling on the incline

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A sphere is released on a smooth inclined plane from the top. When it moves down its angular momentum is:
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A disc of mass M and radius R is rolling with angular speed ω on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin O is 

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