As shown in the figure, a metallic rod of linear density $0.45 \mathrm{kg}{ \mathrm{m}}^{-1}$ is lying horizontally on a smooth incline plane which makes an angle of $45°$ with the horizontal. The minimum current flowing in the rod required to keep it stationary, when $0.15 \mathrm{T}$ magnetic field is acting on it in the vertically upward direction, will be

(Use $g=10 \mathrm{m} {\mathrm{s}}^{-2}$)

A triangular shaped wire carrying $10 \mathrm{A}$ current is placed in a uniform magnetic field of $0.5 \mathrm{T}$, as shown in figure. The magnetic force on segment $CD$ is (Given $BC=CD=BD=5 \mathrm{cm}$).

A wire $X$ of length $50 \mathrm{cm}$ carrying a current of $2 \mathrm{A}$ is placed parallel to a long wire $Y$ of length $5 \mathrm{m}$. The wire $Y$ carries a current of $3 \mathrm{A}$. The distance between two wires is $5 \mathrm{cm}$ and currents flow in the same direction. The force acting on the wire $Y$ is :

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