EASY
JEE Main
IMPORTANT
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Assertion: First law of thermodynamics can be applied only for an ideal or real gas system.

Reason: First law of thermodynamics is nothing but law of conservation of energy.

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Important Questions on The First Law of Thermodynamics

EASY
JEE Main
IMPORTANT

Assertion: There are two processes : Process 1 is pV= constant and process 2 is pV2= constant. In both the processes volume of gas is increased from V1 to V2. Initial coordinates p1, V1 of the gas were the same. Then, more work is done by the gas in process 1.

Reason: In second process pressure drops more rapidly with increase in volume.

EASY
JEE Main
IMPORTANT

Assertion: Any process taking place in the atmosphere is considered as an isobaric process.

Reason: Work done by the system in that case is p0ΔV. Where, p0 is atmospheric pressure.

EASY
JEE Main
IMPORTANT

Assertion: During melting of ice work done by surrounding on (ice + water) system is positive.

Reason: Volume of the given system decreases on melting of ice.

EASY
JEE Main
IMPORTANT

Assertion: Molar heat capacity cannot be defined for an isothermal process.

Reason: In isothermal process pV versus T graph is a dot.

EASY
JEE Main
IMPORTANT

Assertion: If the initial and the final volumes are equal, then work done by the gas is zero.

Reason In an isochoric process the initial and the final volumes are equal and work done by gas is zero.

EASY
JEE Main
IMPORTANT

Assertion: In adiabatic expansion the product of p and V always decreases.

Reason: In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.

EASY
JEE Main
IMPORTANT

Assertion: In isobaric process QΔU is equal to γ=CpCV of the gas.

Reason: For monoatomic gas ratio QΔU in the isobaric process is equal to 53.

EASY
JEE Main
IMPORTANT

A thermodynamic system is taken from an initial state with internal energy Ui=100 J to the final state f along two different paths iaf and ibf as schematically shown in the figure. The work done by the system along the paths af ,ib and bf are Waf=200 J,Wib=50 J and Wbf=100 J respectively. The heat supplied to the system along the path iaf, ib and bf are Qiaf, Qib and Qbf respectively. If the internal energy of the system in the state b is Ub=200 J and Qiaf =500 J, then the ratio QbfQib is

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