Assertion: We cannot find electric field from Gauss's law for unsymmetrical charge distribution.

Reason: Gauss's law is not applicable for unsymmetrical charge distribution.

An electric flux of $-6\times {10}^{-3} \mathrm{N} {\mathrm{m}}^2 {\mathrm{C}}^{-1}$ passes normally through a spherical Gaussian surface of radius $10 \mathrm{cm}$, due to a point charge placed at its centre.

What is the charge enclosed by the Gaussian surface?

An electric flux of $6\times {10}^3 {\mathrm{Nm}}^2{\mathrm{C}}^{-1}$ passes through a spherical Gaussian surface of radius $10 \mathrm{cm}$ due to the charge placed at its centre.

If the radius of the Gaussian surface is doubled how much flux would pass through the surface?