Assertion: When a particle is at an extreme position performing SHM, its momentum is equal to zero.

Reason: At the extreme position, the velocity of a particle performing SHM is equal to zero.

Assertion: In a compound pendulum, if the suspension point and centre of oscillation are mutually interchanged, then no change in a time period is obtained.

Reason: Length of the equivalent simple pendulum remains same in both the case.

Assertion: In SHM, the motion is to and fro and periodic.

Reason: Velocity of the particle, $v=\omega \sqrt{a^2-x^2}$ (where $x$ is displacement)

The oscillation of a body on a smooth horizontal surface is represented by the equation, $x=A\cos \left(\omega t\right)$, where $x=$displacement at time $t$, $\omega$$=$frequency of oscillation. Which one of the following graph shows correctly the variation $a$ with $t$?

Here, $a=$ acceleration at time $t$,

$T=$ time period.