Assertion : When identical cells are connected in parallel to an external load, the effective e.m.f. increases.

Reason : All the cells will be sending unequal currents to the external load in the same direction.

If the reading of the ammeter $A_1$ in the figure is $2.4 \mathrm{A}$. Neglecting the resistances of the ammeters, the reading of the ammeter $A_2$ will be

Two cells of emf $10 \mathrm{V} \mathrm{and} 15 \mathrm{V}$ are connected in parallel to each other between points $A \mathrm{and} B.$ The cell of emf $10 \mathrm{V}$ is ideal but the cell of emf $15 \mathrm{V}$ has internal resistance $1 \mathrm{\Omega }$. The equivalent emf between $A$ and $B$ is:

An electric current passes through non-uniform cross-section wire made of homogeneous and isotropic material. If the $j_{\mathrm{A}}$ and $j_{\mathrm{B}}$ be the current densities and $E_{\mathrm{A}}$ and $E_{\mathrm{B}}$ be the electric field intensities at $A$ and $B$, respectively, then

Figure shows a potentiometer. Length of the potentiometer wire $AB$ is $100 \mathrm{cm}$ and its resistance is $100\Omega$. EMF of the battery $E$ is $2 \mathrm{V}$. A resistance $R$ of $50\Omega$ draws current from the potentiometer. What is the voltage across $R$ when the sliding contact $C$is at the mid-point of $AB ?$