MEDIUM
JEE Main
IMPORTANT
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Assume that limθ-1fθ exists and θ2+θ-2θ+3f(θ)θ2θ2+2θ-1θ+3 holds for a certain interval containing the point, θ=-1 then limθ-1fθ:
 

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Important Questions on Limits

HARD
JEE Main
IMPORTANT
Let fx=limntan-1tanx1+logexn,  x2n+1π2, then
 
MEDIUM
JEE Main
IMPORTANT
limn3·2n+1-4·5n+15·2n+7·5n=
 
EASY
JEE Main
IMPORTANT
limx2+xsinx-2x-22= (where . denotes the fractional part of x).