HARD
JEE Main/Advance
IMPORTANT
Earn 100

At 46°C,Kp for the reaction N2O4(g)2NO2(g) is 0.667 atm. Compute the percent dissociation of N2O4 at 46°C at a total pressure of 380 Torr.

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Important Questions on Equilibrium

HARD
JEE Main/Advance
IMPORTANT
At some temperature and under a pressure of 4 atm,PCl5 is 10% dissociated. Calculate the pressure at which PCl5 will be 20% dissociated, temperature remaining same.
HARD
JEE Main/Advance
IMPORTANT
In a mixture of N2 and H2 in the ratio of 1: 3 at 64 atmospheric pressure and 300°C, the percentage of ammonia under equilibrium is 33.33 by volume. If the equilibrium constant of the reaction using the equation.

N2g+3H2g2NH3g is 1.3×10-Z

then calculate value of z.

HARD
JEE Main/Advance
IMPORTANT
The system N2O42NO2 maintained in a closed vessel at 60°C & pressure of 5 atm has an average (i.e. observed) molecular weight of 69, at what pressure at the same temperature would the observed molecular weight be (2303) ?
HARD
JEE Main/Advance
IMPORTANT
The vapour density of N2O4 at a certain temperature is 30 . Calculate the percentage dissociation of N2O4 at this temperature. N2O4(g)2NO2(g).
HARD
JEE Main/Advance
IMPORTANT
Solid Ammonium carbamate dissociates as : NH2COONH4(s)2NH3(g)+CO2(g). In a closed vessel solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH3 at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.
HARD
JEE Main/Advance
IMPORTANT
A sample of CaCO3(s) is introduced into a sealed container of volume 0.821 litre & heated to 1000 K until equilibrium is reached. The equilibrium constant for the reaction CaCO3(s)CaO(s)+CO2(g) is 4×102 atm at this temperature. Calculate the mass of CaO present at equilibrium.
MEDIUM
JEE Main/Advance
IMPORTANT
Anhydrous calcium chloride is often used as a dessicant. In the presence of excess of CaCl2, the amount of the water taken up is governed by Kp=6.4×1085 for the following reaction at room temperature, CaCl2(s)+6H2O(g)CaCl2·6H2O(s). The equilibrium vapour pressure of water in a closed vessel that contains CaCl2(s) is x×10-y then calculate value of yx.
EASY
JEE Main/Advance
IMPORTANT
20.0 grams of CaCO3(s) were placed in a closed vessel, heated & maintained at 727°C under equilibrium CaCO3(s)CaO(s)+CO2(g) and it is found that 75% of CaCO3 was decomposed. What is the value of Kp ? The volume of the container was 15 litres.