At equilibria, select the false statement, considering the given equation:
${\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{H}}_3{\mathrm{O}}^{+}+{\mathrm{CH}}_3{\mathrm{COO}}^{-}$
${\mathrm{H}}_2{\mathrm{SO}}_4+{\mathrm{CH}}_3\mathrm{COOH}\rightleftharpoons {\mathrm{CH}}_3{\mathrm{COOH}}_2^{+}+{\mathrm{HSO}}_4^{-}$
${\mathrm{H}}_2{\mathrm{SO}}_4+{\mathrm{HNO}}_3\rightleftharpoons {\left[{\mathrm{H}}_2{\mathrm{NO}}_3\right]}^{+}+{\mathrm{HSO}}_4^{-}$
${\mathrm{NH}}_3+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{NH}}_4^{+}+{\mathrm{OH}}^{-}$

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Weak Electrolyte

An electrolyte which completely dissociates into ions is:

In the reaction $\mathrm{B}(\mathrm{OH}{)}_3+2{\mathrm{H}}_2\mathrm{O}⟶{\left[\mathrm{B}(\mathrm{OH}{)}_4\right]}^{-}+{\mathrm{H}}_3\mathrm{O}$

$\mathrm{B}(\mathrm{OH}{)}_3$ functions as

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Strong Electrolyte

Differentiate between the following pair based on the information given in the brackets.

• Conductor and electrolyte (conducting particles)