At equilibrium, reaction stops.

Graph of a reversible process;

${\mathrm{N}}_2+3{\mathrm{H}}_2 \stackrel{}{\rightleftharpoons } 2{\mathrm{NH}}_3+\mathrm{Heat}$

is given. Analyse the graph and answer the following question.

Identify the part of the graph which represents the forward reaction

[ OA, BA, AC]

Graph of a reversible process,

is given. Analyse the graph and answer the following question.

From the given statements, select the correct ones regarding chemical equilibrium.

(i0 The chemical equilibrium is 'static' at the molecular level.

(ii) Both reactants and products co-exist.

(iii) The rates of forward reaction and backward reactions are equal.

(iv) Chemical equilibrium is attained in an open system.

Using the data provided, find the value of equilibrium constant for the following reaction at $298 \mathrm{K}$ and $1$ atm pressure. ${\mathrm{NO}}_{\left(\mathrm{g}\right)}+\frac{1}{2}{\mathrm{O}}_2( \mathrm{g})\rightleftharpoons {\mathrm{NO}}_2( \mathrm{g})$
${\mathrm{\Delta }}_{\mathrm{f}}{\mathrm{H}}^0\left({\mathrm{NO}}_{\left(\mathrm{g}\right)}\right)=90.4\mathrm{kJ}.{\mathrm{mol}}^{-1}$

${\mathrm{\Delta }}_{\mathrm{f}}{\mathrm{H}}^0\left({\mathrm{NO}}_2\left(\mathrm{g}\right)\right)=32.48\mathrm{kJ}\cdot {\mathrm{mol}}^{-1}$

${\mathrm{\Delta S}}^{\circ }\mathrm{at} 298\mathrm{K}=-70.8\mathrm{J}\cdot {\mathrm{K}}^{-1}\cdot {\mathrm{mol}}^{-1}$

$\mathrm{antilog}(0.50)=3162$

$\mathrm{A}+\mathrm{B}\rightleftharpoons \mathrm{C}+2\mathrm{D}.....\left(\mathrm{i}\right)$

$\mathrm{A}+\mathrm{E}\rightleftharpoons \mathrm{C}+\mathrm{F}\dots \dots \dots .\left(\text{ii}\right)$

If ${\mathrm{K}}_1$ and ${\mathrm{K}}_2$ are equilibrium constants for the reactions $\left(\mathrm{i}\right)$ and $\left(\mathrm{ii}\right)$, respectively, then find out the equilibrium constant for the reaction $\mathrm{E}+2\mathrm{D}\rightleftharpoons \mathrm{B}+\mathrm{F}$.

Among the following points indicated on the graph, which one represents equilibrium?

K_p for the reaction
${\mathrm{CuSO}}_4·3{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{s}\right)}+2{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{g}\right)}\to {\mathrm{CuSO}}_4·5{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{s}\right)}$   is $1·0\times 10^4 {\text{atm}}^{-2}$  at certain  temperature. What lowest relative humidity of air can be achieved using $CuS{O}_4.3H_{2}O$ as drying agent at that temperature ?
Aqueous tension at the given temperature = 16 torr

Represent the union of two sets by Venn diagram for each of the following.

$X=\{x | x$ is a prime number between $80$ and $100\}$

$Y=\{y | y$ is an odd number between $90$ and $100\}$