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At how many maximum points, the velocity of a simple pendulum is same

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Important Questions on Simple Harmonic Motion

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Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be
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A particle is executing SHM of frequency 300 Hz and with amplitude 0.1 cm. Its maximum velocity will be
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The velocity of a particle in SHM at displacement y from the mean position is (a=amplitude, ω=angular frequency).
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The displacement of a particle varies according to the relation x=4(cos πt+sin πt). The amplitude of the particle is

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A particle executes simple harmonic motion between x=-A and x=+A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
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The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=43 s is

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A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
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A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is: