Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 8

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Average value of A.C. current in a half time period may be

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Important Questions on Alternating Current

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 9

An alternating current is given by the equation

i = i_{1} \cos ω t + i_{2} \sin ω t .

The rms current is given by

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 10

The peak value of A.C. is

2 \sqrt{2} amp .

, its apparent value is- (in ampere)

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 11

RMS value of current

i = 3 + 4 \sin (ω t + \frac{π}{3}) A

is:

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 12

The peak value of an alternating e.m.f given by

E = E_{0} \cos ω t,

is

10 V

and frequency is

50 Hz .

At time

t = (\frac{1}{600}) \sec,

the instantaneous value of e.m.f is:

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 13

An alternating voltage is given by,

e = e_{1} \sin ω t + e_{2} \cos ω t

. Then the root mean square value of voltage is given by :

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 14

An AC voltage is given by :

E = E_{0} \sin \frac{2 π t}{T}

. Then the mean value of voltage is calculated over time interval of

\frac{T}{2}

seconds:

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 15

The voltage of an AC source varies with time according to the equation,

V = 100 \sin 100 π t \cos 100 π t

where

t

is in second and

V

is in volt. Then:

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Alpha Question Bank for Medical: Physics>Chapter 28 - Alternating Current>Exercise-1>Q 16

An AC voltage of

V = 220 \sqrt{2} \sin (2 π 50 t + \frac{π}{2})

is applied across a DC voltmeter, its reading will be: