${\mathrm{B}}_2{\mathrm{H}}_6+2 \mathrm{NaH}\stackrel{{\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_2\mathrm{O}}{\to }$ .

Choose from the following:

A: $2 {\mathrm{NaBH}}_4$

B: ${\mathrm{NaBH}}_4$

The structure of diborane ${\mathrm{B}}_2{\mathrm{H}}_6$ is given below. Identify the bond angles $\mathrm{x}, \mathrm{y}.$ In diborane, which bonds are commonly known as banana-bonds

The correct match is

Identify the correct statement for ${\mathrm{B}}_2{\mathrm{H}}_6$ from those given below.

(A) In ${\mathrm{B}}_2{\mathrm{H}}_6$, all $\mathrm{B}-\mathrm{H}$ bonds are equivalent.

(B) In ${\mathrm{B}}_2{\mathrm{H}}_6$, there are four $3$-centre- $2$-electron bonds.

(C) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a Lewis acid.

(D) ${\mathrm{B}}_2{\mathrm{H}}_6$ can be synthesized from both ${\mathrm{BF}}_3$ and ${\mathrm{NaBH}}_4$.

(E) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a planar molecule.

Choose the most appropriate answer from the options given below :

Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of ${\mathrm{NaBH}}_4$ with ${\mathrm{I}}_2$
(b) Each boron atom is in ${\mathrm{sp}}^2$ hybridized state
(c) Diborane has one bridged $3$ centre-$2$-electron bond
(d) Diborane is a planar molecule

The option with correct statement(s) is 

Which of the following reactions can be used to prepare diborane?

$\mathrm{I}{)}^{} {\mathrm{BF}}_3+LiAl{\mathrm{H}}_4\stackrel{\mathrm{ether}}{\to }$

$\mathrm{II})$ ${\mathrm{BF}}_3+\mathrm{NaH}\stackrel{450 \mathrm{K}}{⟶}$
$\mathrm{III}) {\mathrm{Na}}_2{\mathrm{B}}_4{\mathrm{O}}_7+{\mathrm{H}}_2\mathrm{O}⟶$
$\mathrm{IV}) {\mathrm{NaBH}}_4+{\mathrm{I}}_2⟶$

The geometry around boron in the product '$\mathrm{B}$' formed from the following reaction is

${\mathrm{BF}}_3+\mathrm{NaH}\stackrel{450 \mathrm{K}}{⟶}\mathrm{A}+\mathrm{NaF}$

$\mathrm{A}+{\mathrm{NMe}}_3\to \mathrm{B}$