By what number should ${\left(\frac{1}{2}\right)}^{-1}$ be multiplied so that the product may be equal to ${\left(\frac{-4}{ 7}\right)}^{-1}$?

Simplify${\left(\frac{3}{2}\right)}^{-1}\times {\left(\frac{3}{2}\right)}^{-1}\times {\left(\frac{3}{2}\right)}^{-1}\times {\left(\frac{3}{2}\right)}^{-1}$. (Write in proper fraction)

Write each of the following in exponential form:

${\left(\frac{2}{5}\right)}^{-2}\times {\left(\frac{2}{5}\right)}^{-2}\times {\left(\frac{2}{5}\right)}^{-2}$. If the answer is ${\left(\frac{2}{5}\right)}^k$, find $k.$

Evaluate:

$5^{-2}$

Evaluate:

$(-3{)}^{-2}$

Evaluate:

 ${\left(\frac{1}{3}\right)}^{-4}$

Evaluate: ${\left(\frac{-1}{ 2}\right)}^{-1}$

Express the following as a rational number in the form $\frac{p}{q}$:

$6^{-1}$