EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET - 5 August 2021 Shift 1>Q 7

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IMPORTANT

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Calculate the activation energy of a reaction, whose rate constant doubles on raising the temperature from $300 K$ to $600 K .$

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Important Questions on Chemical Kinetics

EASY

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET 2019 (03-May Shift-2)>Q 1

The following results have been obtained during the kinetic studies of reaction:
$2 NO + 2 H_{2} ⟶ N_{2} + 2 H_{2} O$

Expt	$\frac{- d [NO]}{dt}$ ${molL}^{- 1} s^{- 1}$	$[NO]$ ${molL}^{- 1}$	$[H_{2}]$ ${molL}^{- 1}$
$1$ .	$4.8 \times 10^{- 5}$	$1 \times 10^{- 2}$	$1 \times 10^{- 3}$
$2$ .	$43.2 \times 10^{- 5}$	$3 \times 10^{- 2}$	$1 \times 10^{- 3}$
$3$ .	$86.4 \times 10^{- 5}$	$3 \times 10^{- 2}$	$2 \times 10^{- 3}$

EASY

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET 2021 (04-Aug Shift-1)>Q 2

What will be the overall order of a reaction for which the rate expression is given as
Rate

= K [A]^{\frac{1}{2}} [B]^{\frac{3}{2}}

MEDIUM

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET 2021 (04-Aug Shift-2)>Q 3

In the sequence of reaction

A \overset{k_{1}}{⟶} X \overset{k_{2}}{⟶} Y \overset{k_{3}}{⟶} Z

k_{3} > k_{2} > k_{1},

then the rate determining step is

MEDIUM

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET - 5 August 2021 Shift 2>Q 4

For a first order reaction

t_{1 / 2}

is

1200 s .

The specific rate constant in

s^{- 1}

is

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET 2020 (9-Sep Shift-1)>Q 5

The rate of chemical reaction doubles with every

10^{o} C

rise in temperature. If the reaction is carried out in the vicinity of

22^{o} C

, the activation energy of the reaction is (Given

R = 8.3 J K^{- 1} {mol}^{- 1}, \ln 2 = 0.69

and

\ln 3 = 1.1

)

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET 2018 (04-May Shift-1)>Q 6

If the rate constants of a reaction at $500 K$ and $700 K$ are $0.002 s^{- 1}$ and $0.06 s^{- 1}$ , respectively, the value of activation energy is

$(R = 8.314 J {mol}^{- 1} K^{- 1}, \log 3 = 0.477)$

HARD

TS EAMCET

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 18 - Chemical Kinetics>TS EAMCET - 5 August 2021 Shift 1>Q 7

Calculate the activation energy of a reaction, whose rate constant doubles on raising the temperature from

300 K

to

600 K .