Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius $8 \mathrm{c}\mathrm{m}$ each.

Given figure depicts an archery target marked with its five-scoring areas from the centre outwards as Gold, Red, Blue, Black and White. The diameter of the region representing Gold score is $21 \mathrm{c}\mathrm{m}$ and each of the other bands is $10.5 \mathrm{c}\mathrm{m}$ wide. Find the area of each of the five scoring regions. $\left(\mathrm{use\pi }=\frac{22}{7}\right)$

If the perimeter and the area of a circle are numerically equal, then the radius of the circle is (Use $\pi =\frac{22}{7}$).