Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 23

EASY

JEE Main

IMPORTANT

Earn 100

Calculate the equivalent weight of ${SO}_{2}$ in the following reactions:

$(a) {SO}_{2} + 2 H_{2} S = 3 S + 2 H_{2} O$

$(b) 5 {SO}_{2} + 2 {KMnO}_{4} + 2 H_{2} O = K_{2} {SO}_{4} + 2 {MnSO}_{4} + 2 H_{2} {SO}_{4}$

Important Questions on Chemical Equivalence

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 1

Fe

forms two chlorides,

{FeCl}_{2}

and

{FeCl}_{3}

. Does

Fe

have the same value of equivalent weight in its compounds?

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 2

The equivalent weight of metal is

12 .

What is the equivalent weight of its oxide?

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 3

0.2 g

of oxygen and

3.17 g

of a halogen combine separately with the same amount of metal. What is the equivalent weight of the halogen?

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 4

Arsenic forms two oxides, one of which contains

65.2 %

and the other,

75.7 %

of the element. Determine the equivalent weight of arsenic in both cases.

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 5

1.80 g

of metal oxide required

833 mL

of hydrogen at NTP to be reduced to its metal. Find the equivalent weight of the oxide and the metal.

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 6

A certain amount of metal, whose equivalent weight is

28,

displaces

0.7 litre

of hydrogen measured at NTP from an acid. Calculate the weight of the metal.

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 7

$9.44 g$ of a metal oxide is formed by the combination of $5 g$ of the metal. Calculate the equivalent weight of the metal.

Give the answer up to two places of decimal.

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 6 - Chemical Equivalence>PROBLEMS>Q 8

14.7 g

of sulphuric acid was needed to dissolve

16.8 g

of a metal. Calculate the equivalent weight of the metal and the volume of hydrogen liberated at NTP.