Calculate the mass of an elementary particle, which is accelerated to twice the velocity of light with the precision $\pm 1\%$ and has $1.05\times {10}^{-13} \mathrm{m}$ uncertainty in position. $\left(h=6.6\times {10}^{-34} \mathrm{kg}{ \mathrm{m}}^2{ \mathrm{s}}^{-1}\right)$

An accelerated electron has a speed of $5\times {10}^6{ \mathrm{ms}}^{-1}$ with an uncertainty of $0.02\%$. The uncertainty in finding its location while in motion is $x\times {10}^{-9} \mathrm{m}$.
The value of $x$ is __________. (Nearest integer)

[Use mass of electron$=9.1\times {10}^{-31} \mathrm{kg}$,

$\left.\mathrm{h}=6.63\times {10}^{-34}\mathrm{Js},\mathrm{\pi }=3.14\right]$

If the uncertainty in velocity and position of a minute particle in space are, $2.4\times {10}^{-26}\left({\mathrm{ms}}^{-1}\right)$ and ${10}^{-7}\left(\mathrm{m}\right)$ respectively. The mass of the particle in $\mathrm{g}$ is___(Nearest integer)

(Given : $\mathrm{h}=6.626\times {10}^{-34}\mathrm{Js}$)

If a cricket ball of weight $0.1 \mathrm{kg}$ has an uncertainty of $0.15 \mathrm{m}·{\mathrm{s}}^{-1}$ in its velocity, then the uncertainty in the position of the cricket ball is $\underline{ }$

A ball weighing $10 \mathrm{g}$ is moving with a velocity of $90 \mathrm{m} {\mathrm{s}}^{-1}.$ If the uncertainty in its velocity is $5\%$, then the uncertainty in its position is _  $\times {10}^{-33} \mathrm{m}.$ (Rounded off to the nearest integer)

[Given: $\mathrm{h}=6.63\times {10}^{-34} \mathrm{Js}$]