Calculate the orbital velocity of a satellite revolving near the earth, if the radius of the earth is 6 . 4 × 10 6 m and acceleration due to gravity 10 ms - 2 . What will be the orbital velocity if the satellite be at a height of 200 km from the earth's surface?

The required expression of orbital velocity is for a satellite orbiting near earth's surface is V o = gR = 10 × 6 . 4 × 10 6 = 8 × 10 3 ms - 1 = 8 kms - 1 and for a satellite at the height of 200 km the required expression of the orbital velocity will be h = 200 km = 200 × 10 3 m = 2 × 10 5 m V o = gR 2 ( R + h ) = 10 × ( 6 . 4 × 10 6 ) 2 6 . 4 × 10 6 + 2 × 10 5 = 7 × 10 3 ms - 1 = 7 kms - 1

Calculate the orbital velocity of a satellite revolving near the earth, if the radius of the earth is 6 . 4 × 10 6 m and acceleration due to gravity 10 ms - 2 . What will be the orbital velocity if the satellite be at a height of 200 km from the earth's surface?

The required expression of orbital velocity is for a satellite orbiting near earth's surface is V o = gR = 10 × 6 . 4 × 10 6 = 8 × 10 3 ms - 1 = 8 kms - 1 and for a satellite at the height of 200 km the required expression of the orbital velocity will be h = 200 km = 200 × 10 3 m = 2 × 10 5 m V o = gR 2 ( R + h ) = 10 × ( 6 . 4 × 10 6 ) 2 6 . 4 × 10 6 + 2 × 10 5 = 7 × 10 3 ms - 1 = 7 kms - 1

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Calculate the orbital velocity of a satellite revolving near the earth, if the radius of the earth is $6.4 \times 10^{6} m$ and acceleration due to gravity $10 {ms}^{- 2} .$ What will be the orbital velocity if the satellite be at a height of $200 km$ from the earth's surface?

Important Questions on Gravitation : Planets and Satellites

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 24

A $500 km$ satellite revolve around the earth at a height of $10^{3} km$ above the earth's surface. Calculate assuming circular orbit: speed of satellite, Given: radius of the earth $6.4 \times 10^{6} m, g = 9.80 {ms}^{- 2} .$

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 24

A $500 km$ satellite revolve around the earth at a height of $10^{3} km$ above the earth's surface. Calculate assuming circular orbit: angular velocity of satellite, Given: radius of the earth $6.4 \times 10^{6} m, g = 9.80 {ms}^{- 2} .$

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 24

A $500 kg$ satellite revolve around the earth at a height of $10^{3} km$ above the earth's surface. Calculate assuming circular orbit: gravitational force of the earth satellite, Given: radius of the earth $6.4 \times 10^{6} m, g = 9.80 {ms}^{- 2} .$

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 25

A satellite is revolving around the earth in a circular orbit of radius

8000 km

. With what speed this satellite be projected in the orbit? What will be its period of revolution?

(g = 9.8 {ms}^{- 2}, radius of the earth 6400 km) .

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 26

An earth-satellite is revolving at a height of

1800 km

from the earth's surface. Radius of the earth is

6300 km

and acceleration due to gravity is

10 {ms}^{- 2}

, Find out orbital velocity of satellite.

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IMPORTANT

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 26

An earth-satellite is revolving at a height of

1800 km

from the earth's surface. Radius of the earth is

6300 km

and acceleration due to gravity is

10 {ms}^{- 2}

, Find out radial acceleration of the satellite.

HARD

11th ICSE

IMPORTANT

ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 26

An earth-satellite is revolving at a height of

1800 km

from the earth's surface. Radius of the earth is

6300 km

and acceleration due to gravity is

10 {ms}^{- 2}

, Find out period of revolution of the satellite.

HARD

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ISC Physics Class XI Part 1>Chapter 15 - Gravitation : Planets and Satellites>NUMERICALS>Q 27

The distance between the centre of the earth and the moon is

60

times the radius of the earth. Calculate the centripetal acceleration of the moon. Acceleration due to gravity on the earth's surface

= 10 {ms}^{- 2} .

Calculate the orbital velocity of a satellite revolving near the earth, if the radius of the earth is 6.4×106m and acceleration due to gravity 10ms-2. What will be the orbital velocity if the satellite be at a height of 200km from the earth's surface?

Important Questions on Gravitation : Planets and Satellites

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Calculate the orbital velocity of a satellite revolving near the earth, if the radius of the earth is $6.4 \times 10^{6} m$ and acceleration due to gravity $10 {ms}^{- 2} .$ What will be the orbital velocity if the satellite be at a height of $200 km$ from the earth's surface?