Calculate the steady-state current through $2\mathrm{\Omega }$ resistor in the circuit shown in Fig. The internal resistance of the battery is negligible and $\mathrm{C}=2\mathrm{\mu F}$

As shown in Fig., a variable rheostat of $2 \mathrm{k\Omega }$ is used to control the potential difference across a $500 \mathrm{\Omega }$ load.

If the resistance $\mathrm{AB}$ is $500 \mathrm{\Omega }$, what is the potential difference across the load?

As shown in Fig., a variable rheostat of $2 \mathrm{k\Omega }$ is used to control the potential difference across a $500 \mathrm{\Omega }$ load.

If the load is removed, what should be the resistance at $\mathrm{BC}$ to get $40 \mathrm{V}$ between $\mathrm{B}$ and $\mathrm{C}$ ?

In the circuit shown in Fig., both the ammeter and the cell have negligible resistance. Three external resistors are identical. When the switch $\mathrm{S}$ is opened, the ammeter reads $0.6 \mathrm{A}$. What will the ammeter read when the switch $\mathrm{S}$ is closed?

If the galvanometer in the circuit (Fig.) reads zero, find the value of resistor $\mathrm{R}$. The $12 \mathrm{V}$ source has negligible internal resistance. If cool air is blown across the wire wound resistance, what effect will be noticed and why ?

 As shown in Fig. , A and B are two points on a uniform ring of resistance $\mathrm{R}.$ If the part $\mathrm{AB}$ of the ring subtends an angle $\mathrm{\theta }$ at the centre $\mathrm{C}$ of the ring, find the equivalent resistance of the ring between the points $\mathrm{A}$ and $\mathrm{B}.$