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Calculate the work done for the following. F-d curves to

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Important Questions on Work, Energy and Power

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A force F=Kx2 acts on a particle at an angle of 600 with the x-axis. The work done in displacing the particle from x1 to x2 will be -
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The work done against gravity in taking 10 kg mass at 1 m height in 1 s will be:
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A force of 10N displaces an object by 10m. If work done is 50J then direction of force make an angle with direction of displacement :
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A body of mass 6 kg under a force that causes displacement in it given S=t24 m, where t is time. The work done by the force in 2 seconds is
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A force F=5i^+4j^ N acts on a body and produces a displacement s=6i^-5j^+3k^ m. The work done will be
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A force F acting on an object varies with distance x as shown here. The work done by the force in moving the object from x=0 to x=6 m is

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A stone of mass m is tied to a string of length 2 m at one end and by holding the second end, it is whirled into a horizontal circle. Then, the work done will be,
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A particle is moved from a position, r1=(3i^+2j^-6k^) m to a position, r2=14i^ +13j^-9k^ m under the action of a force, F=4i^+j^+3k^ N. The work done is equal to,