A solid metal sphere of volume 0 . 31 m 3 is dropped in an ocean where water pressure is 2 × 10 7 N m 2 • Calculate change in volume of the sphere if bulk modulus of the metal is 6 . 1 × 10 10 N m 2 .

Given - V = 0 . 31 m 3 , K = 6 . 1 × 10 10 N m 2 , P = 2 × 10 7 N m 2 Therefore K = - P Δ V V ⇒ Δ V = - P V K = 2 × 10 7 × 0 . 31 6 . 1 × 10 10 = 0 . 101 × 10 - 3 ≈ 10 - 4 m 3

E M B I B E

Physics>Chapter 6 - Mechanical Properties of Solids>Exercises>Q 5

EASY

11th Maharashtra Board

IMPORTANT

Earn 100

Calculate the work done in stretching a steel wire of length $2 m$ and cross sectional area $0.0225 m m^{2}$ when a load of $100 N$ is slowly applied to its free end.

Important Questions on Mechanical Properties of Solids

MEDIUM

11th Maharashtra Board

IMPORTANT

Physics>Chapter 6 - Mechanical Properties of Solids>Exercises>Q 5

A solid metal sphere of volume

0.31 m^{3}

is dropped in an ocean where water pressure is

2 \times 10^{7} \frac{N}{m^{2}}

• Calculate change in volume of the sphere if bulk modulus of the metal is

6.1 \times 10^{10} \frac{N}{m^{2}}

.

EASY

11th Maharashtra Board

IMPORTANT

Physics>Chapter 6 - Mechanical Properties of Solids>Exercises>Q 5

A wire of mild steel as initial length

1.5 m

and diameter

0.60 m m

gets extended by

6.3 m m

when a certain force is applied to it. If Young's modulus of mild steel is

2.1 \times 10^{11} \frac{N}{m^{2}}

calculate force applied.

HARD

11th Maharashtra Board

IMPORTANT

Physics>Chapter 6 - Mechanical Properties of Solids>Exercises>Q 5

A composite wire is prepared by joining a tungsten wire and steel wire end to end. Both the wires are of the same length and the same area of cross section. If this composite wire is suspended to a rigid support and a force is applied to its free end, it gets extended by 3.25mm. Calculate the increase in length of tungsten wire and steel wire separately.

HARD

11th Maharashtra Board

IMPORTANT

Physics>Chapter 6 - Mechanical Properties of Solids>Exercises>Q 5

A steel wire having cross sectional area 1.2m