Can you construct the quadrilateral $\mathrm{PLAN}$ if $\mathrm{PL}=6 \mathrm{cm}$, $\mathrm{LA}=9.5 \mathrm{cm}$, $\angle \mathrm{P}=75°$ , $\angle \mathrm{L}=15°$ and $\angle \mathrm{A}=140°$ .

(Draw a rough sketch in each case and analyse the figure) State the reasons for your conclusion

Construct quadrilaterals with the measurements given below:

Quadrilateral $\mathrm{HELP}$ with $\mathrm{HE}=6 \mathrm{cm}, \mathrm{EL}=4.5 \mathrm{cm}, \angle \mathrm{H}={60}^{\mathrm{o}}, \angle \mathrm{E}={105}^{\mathrm{o}}$ and $\angle \mathrm{P}={120}^{\mathrm{o}}$.

Construct quadrilaterals with the measurements given below:

Parallelogram $\mathrm{GRAM}$ with $\mathrm{GR}=\mathrm{AM}=5 \mathrm{cm}, \mathrm{RA}=\mathrm{MG}=6.2 \mathrm{cm}$ and $\angle \mathrm{R}={85}^{\mathrm{o}}$.

Construct quadrilaterals with the measurements given below:

Rectangle $\mathrm{FLAG}$ with sides $\mathrm{FL}=6 \mathrm{cm}$ and $\mathrm{LA}=4.2 \mathrm{cm}$.

Do you construct the above quadrilateral $\mathrm{ABCD}$ by taking $\mathrm{BC}$ as base instead of $\mathrm{AB}$? If So, draw a rough sketch and explain the various steps involved in the construction.

Construct following quadrilaterals-

Quadrilateral $\mathrm{PQRS}$ with $\mathrm{PQ}=3.6 \mathrm{cm}, \mathrm{QR}=4.5 \mathrm{cm}, \mathrm{RS}=5.6 \mathrm{cm}, \angle \mathrm{PQR}={135}^{\mathrm{o}}$ and $\angle \mathrm{QRS}={60}^{\mathrm{o}}$.

Construct following quadrilaterals-

Quadrilateral $\mathrm{LAMP}$ with $\mathrm{AM}=\mathrm{MP}=\mathrm{PL}=5 \mathrm{cm}, \angle \mathrm{M}={90}^{\mathrm{o}}$ and $\angle \mathrm{P}={60}^{\mathrm{o}}$.

Construct following quadrilaterals-

Trapezium $\mathrm{ABCD}$ in which $\mathrm{AB}\parallel \mathrm{CD}, \mathrm{AB}=8 \mathrm{cm}, \mathrm{BC}=6 \mathrm{cm}, \mathrm{CD}=4 \mathrm{cm}$ and $\angle \mathrm{B}={60}^{\mathrm{o}}$.

Can you construct the above quadrilateral (rhombus) taking $\mathrm{BD}$ as a base instead of $\mathrm{AC}$? If not give reason.