Complete the following table.

Numbers	Commutative with respect to
	Addition	Subtraction	Multiplication	Division
Natural numbers	Yes	No	Yes
Whole numbers				No
Integers
Rational Numbers				No

Is $2+(3+0)=(2+3)+0?$

$2+(3+0)=2+3=5$

$(2+3)+0=5+0=5$

$\Rightarrow 2+(3+0)=(2+3)+0$

$a+(b+c)=(a+b)+c$

for any three whole numbers $a, b, c$

$(2-3)-2=? 2-(3-2)=?$

Is $(2-3)-2=2-(3-2)?$

Is $2÷(3÷5)=(2÷3)÷5?$

$2÷\left(3÷5\right)=2÷\frac{3}{5}=2\times \frac{5}{3}=\frac{10}{3}$

$\left(2÷3\right)÷5=\frac{2}{3}÷5=\frac{2}{3}\times \frac{1}{5}=\frac{2}{15}$

$2÷\left(3÷5\right)\ne \left(2÷3\right)÷5$

Is $2+\left[\right(-3)+5)]=[(2+(-3\left)\right]+5?$

$2+\left[\right(-3)+5]=2+[-3+5]=2+2=4$

$[2+(-3\left)\right]+5=[2-3]+5=-1+5=4$

For any three integers $a, b, c$

$a+(b+c)=(a+b)+c$

Is $6-(9-5)=(6-9)-5?$

$10÷ [2÷(-5\left)\right]=[10÷2]÷(-5)?$

$10÷\left[2÷\left(-5\right)\right]=10÷\frac{2}{-5}=10\times \frac{-5}{2}=-25$

Now, $\left[10÷2\right]÷\left(-5\right)=\frac{10}{2}÷\left(-5\right)=5÷\left(-5\right)=\frac{5}{-5}=-1$

Thus, $10÷ [2÷(-5\left)\right]\ne [10÷2]÷(-5)$