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Consider an infinite line charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.

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Important Questions on Electric Flux and Gauss's Law

HARD

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 33

One-fourth of a sphere of radius $R$ is removed as shown in the figure. An electric field $E$ exists parallel to the $x y$ plane. Find the flux through the remaining curved part. Question Image

MEDIUM

JEE Advanced

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PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 34

A spherical shell of radius

R = 1.5 c m

has a charge

q = 20 µ C

uniformly distributed over it. The force exerted by one half over the other half is

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 35

The negative charge $- q_{2}$ is fixed while positive charge $q_{1}$ as well as the conducting sphere $S$ is free to move (refer figure). If the system is released from rest,
Question Image

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 36

A wire of linear charge density

λ

passes through a cuboid of length

l

, breadth

b

and height

h

(l > b > h)

in such a manner that the flux through the cuboid is maximum. The position of the wire is now changed so that the flux through the cuboid is minimum. The ratio of maximum flux to minimum flux will be

EASY

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 37

Consider the situation shown in figure. We find electric field

E

at point

P

using Gauss's law and it comes out to be

E = \frac{σ}{ε_{0}}

. This electric field is due to
Question Image

HARD

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 38

Two parallel conducting plates, each of area

A

, are separated by a distance

d

. Now, the left plate is given a positive charge

Q

. A positive charge

q

of mass

m

is released from a point near the left plate. Find the time taken by the charge to reach the right plate.
Question Image

EASY

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 39

Two large plates are given the charges as shown in figure. Now, the left plate is earthed. Find the amount of charge that will flow from the earth to the plate.
Question Image

HARD

JEE Advanced

IMPORTANT

PHYSICS for Joint Entrance Examination JEE (Advanced) Electrostatics and Current Electricity>Chapter 2 - Electric Flux and Gauss's Law>Exercise>Q 40

The electric field in a region is given by

\vec{E} = \frac{E_{0} x}{l} \hat{i}

.
Find the charge contained inside a cubical volume bounded by the surfaces

x = 0, x = a, y = 0, y = a, z = 0

and

z = a

. Take

E_{0} = 5 \times 10^{3} N C^{- 1}

l = 0.02 m

and

a = 0.01 m

Consider an infinite line charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.

Important Questions on Electric Flux and Gauss's Law

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