MEDIUM
JEE Main/Advance
IMPORTANT
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Consider the following statements
S1: The total number of terms in x2+2x+110 is 21.
S2: The coefficient of x10 in x2+1x20 is C1020.

S3: The middle term in the expansion of (1+x)12 is C612x6.

S4: If the coefficients of the fifth and ninth term in the expansion of (1+x)n are same then n=12.
Now identify the correct combination of true statements.

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Important Questions on Binomial Theorem

MEDIUM
JEE Main/Advance
IMPORTANT
If the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of 214+1314n is 6:1 then value of n is equal to
MEDIUM
JEE Main/Advance
IMPORTANT
The value of the coefficient of x4 in the expansion of 2-x+3x26 is
MEDIUM
JEE Main/Advance
IMPORTANT
The greatest value of n for which 97+79 is divisible by 2n is equal to
MEDIUM
JEE Main/Advance
IMPORTANT
If the coefficient of xn in the expansion of 1-9x+20x2-1 is an+1-bn+1 (where a, b are coprime) then ab is equal to (a>b).
MEDIUM
JEE Main/Advance
IMPORTANT
The coefficient of x9 in the expansion of r=11001+xr is equal to
MEDIUM
JEE Main/Advance
IMPORTANT
If 1-x3n=r=0narxr(1-x)3n-2r,x0 then the value of ar where nN is
HARD
JEE Main/Advance
IMPORTANT
Let 1+x221+xn=k=0n+4ak·xk, If a1,a2 and a3 are in A.P., then the value of n is
HARD
JEE Main/Advance
IMPORTANT
r=0n-1r·Crn12r+3r22r+7r23r+15r24r+m terms =